← Moment Equations

13

Approximate extinction and outbreak probabilities

Mean and variance support probability calculations only after an additional distributional assumption is stated and tested.

Moments do not determine a distribution

Knowing only mean and variance is generally insufficient to determine \(\Pr(I=0)\) or \(\Pr(I\ge K)\). A probability calculation requires an additional distributional assumption or a rigorous bound.

Normal approximation with continuity correction

If \(I(t)\) is approximated by \(N(\mu(t),\sigma^2(t))\), then

\[ \Pr(I(t)=0)\approx \Phi\left(\frac{0.5-\mu(t)}{\sigma(t)}\right), \]
\[ \Pr(I(t)\ge K)\approx 1-\Phi\left(\frac{K-0.5-\mu(t)}{\sigma(t)}\right). \]

The 0.5 correction maps integer thresholds to intervals on a continuous approximation.

Why extinction is particularly difficult

An epidemic distribution may have a point mass at zero and a separate continuous-looking group of surviving outbreaks. A single normal distribution has no point mass and permits negative values, so its extinction approximation can be poor.

Interactive Python laboratory

Interactive PythonMoment-based probability approximations

Output

Run the code to see the result.

Time-specific versus ever crossing

\(\Pr(I(t)\ge20)\) asks whether prevalence is at least 20 at a particular time. It is not the probability that the path has ever reached 20 by that time. Ever-crossing probabilities depend on the whole path and cannot be recovered from marginal moments alone.

What this lesson adds

You can now convert mean and variance into explicitly assumption-dependent probability approximations, apply a continuity correction, validate against CTMC frequencies and distinguish time-specific events from pathwise outbreak events.